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Sintaxe ALIAS no SQLite

您可以通过提供另一个名称(ALIAS)来临时重命名表或列。 表别名的使用意味着在特定的SQLite语句中重命名表。 重命名是一个临时更改,数据库中的实际表名不会更改。

列别名用于重命名表的列,以用于特定的SQLite查询。

语法

以下是table别名的基本语法。

SELECT column1, column2....
FROM table_name AS alias_name
WHERE [condition];

以下是column别名的基本语法。

SELECT column_name AS alias_name
FROM table_name
WHERE [condition];

在线示例

考虑以下两个表,(a)COMPANY表如下-

sqlite> select * from COMPANY;
ID                                      NAME                                      AGE                                      ADDRESS                              SALARY
----------  --------------------  ----------  ----------  ----------
1           Paul                  32          California  20000.0
2           Allen                 25          Texas       15000.0
3           Teddy                 23          Norway      20000.0
4           Mark                  25          Rich-Mond   65000.0
5           David                 27          Texas       85000.0
6           Kim                   22          South-Hall  45000.0
7           James                 24          Houston     10000.0

(b)另一个表格是部门--

ID                                      DEPT                                      EMP_ID
----------  --------------------  ----------
1           Contabilidade de TI            1
2           Engenharia           2
3           Finanças               7
4           Engenharia           3
5           Finanças               4
6           Engenharia           5
7           Finanças               6

现在,下面是TABLE ALIAS我们分别使用C和D作为COMPANY和DEPARTMENT表的别名的用法-

sqlite> SELECT C.ID, C.NAME, C.AGE, D.DEPT
        FROM COMPANY AS C, DEPARTMENT AS D
        WHERE	C.ID = D.EMP_ID;

A seguinte consulta SQLite produzirá o seguinte resultado-

ID                                      NAME                                      AGE                                      DEPT
----------  ----------  ----------  ----------
1           Paul        32          Contabilidade de TI
2           Allen       25          Engenharia
3           Teddy       23          Engenharia
4           Mark        25          Finanças
5           David       27          Engenharia
6           Kim         22          Finanças
7           James       24          Finanças

考虑一个使用示例,COLUMN ALIAS其中COMPANY_ID是ID列的别名,而COMPANY_NAME是name列的别名。

sqlite> SELECT C.ID AS COMPANY_ID, C.NAME AS COMPANY_NAME, C.AGE, D.DEPT
        FROM COMPANY AS C, DEPARTMENT AS D
        WHERE	C.ID = D.EMP_ID;

A seguinte consulta SQLite produzirá o seguinte resultado-

COMPANY_ID	COMPANY_NAME	IDADE	DEPT
----------  ------------  ----------  ----------
1           Paul          32          Contabilidade de TI
2           Allen         25          Engenharia
3           Teddy         23          Engenharia
4           Mark          25          Finanças
5           David         27          Engenharia
6           Kim           22          Finanças
7           James         24          Finanças