Verificação de número Armstrong em programas Python

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In this example, you will learn to check if an n-digit integer is an Armstrong number.

To understand this example, you should understand the followingPython programmingTopic:

• Python if ... else statement

• Python while loop

A positive integer is called an Armstrong order, n if

abcd...　=　an　+　bn　+　cn　+　dn　+　...

If it is3If a number is an n-digit Armstrong number, the sum of the cubes of each digit is equal to the number itself. For example:

153　=　1*1*1　+　5*5*5　+　3*3*3　　//　153It is an Armstrong number.

Source code: Check Armstrong number (3digit)

#　Check if the number is an Armstrong number in Python
#　Accept user input
num　=　int(input("Enter a number: "))
#　Initialize sum
sum　=　0
#　Calculate the sum of cubes of each digit
temp　=　num
while　temp　>　0:
　　　digit　=　temp　%　10
　　　sum　+=　digit　**　3
　　　temp　//=　10
#　Show result
if　num　==　sum:
　　　print(num, "is an Armstrong number")
else:
　　　print(num, "is not an Armstrong number")

Output1

Enter a number:　456
456　Is not an Armstrong number

Output2

Enter a number:　407
407　Is an Armstrong number

Here, we ask the user to enter a number and check if it is an Armstrong number.

We need to calculate the sum of cubes of each digit. Therefore, we initialize the sum to 0 and useModulus operator (%))Get each digit. Divide the number by10The remainder is the last digit of the number. We use the exponent operator to get multidimensional data sets.

Finally, we compare the sum with the original number to draw a conclusion. If they are equal, it is an Armstrong number.

Source code: Check if n-digit number is an Armstrong number

num　=　1634
#　Change the num variable to string
#　And calculate the length (number of digits)
order　=　len(str(num))
#　Initialize sum
sum　=　0
#　Calculate the sum of cubes of each digit
temp　=　num
while　temp　>　0:
　　　digit　=　temp　%　10
　　　sum　+=　digit　**　order
　　　temp　//=　10
#　Show result
if　num　==　sum:
　　　print(num, "is an Armstrong number")
else:
　　　print(num, "is not an Armstrong number")

You can change the value of num in the source code and run it again to test it.

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